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An object thrown vertically up from the ground passes the height 5m twice in an interval of 10 sec. What is its time of flight

An object thrown vertically up from the ground passes the height 5m twice in an interval of 10 sec. What is its time of flight

Grade:11

1 Answers

Abhinav
askIITians Faculty 387 Points
8 years ago
particle passes height 5mtwice in an interval of 10 sec .So it took 5 sec for reaching heighest point of flight.
so
velocity at 5 m height is
0= v- gt
0=v-10*5
v=50
so speed at start = 502= u2- 2*10*5
u= 51 m/s
time taken to reach 5m =.1 sec
so total time of flight = 10.2

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