MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Shane Macguire Grade: upto college level
        An elevator is descending with uniform acceleration. To measure the acceleration, a person in the elevator drops a coin at the moment the elevator starts. The coin is 6ft above the floor of the elevator at the time it is dropped. The person observes that the coin strikes the floor in 1 second. Calculate from these data the acceleration of the elevator.
3 years ago

Answers : (1)

Deepak Patra
askIITians Faculty
474 Points
										Sol. For elevator and coin u = 0

As the elevator descends downward with acceleration a’ (say)
The coin has to move more distance than 1.8 m to strike the floor. Time taken t = 1 sec.
Sc = ut+ ½ a’t2 = 0 + ½ g (1)2 = ½ g
Se = ut+ ½ at2 u + ½ a (1)2 = 1/a2 a
Total distance covered by coin is given by = 1.8 + 1/2 a = 1/2 g
⇒ 1.8 +a/2 = 9.8/2 = 4.9
⇒ a = 6.2 m/s2 = 6.2 × 3.28 = 20.34 ft/s2.
3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: Rs. 2,756
  • View Details
Get extra Rs. 413 off
USE CODE: COUPON10
  • Complete Physics Course - Class 11
  • OFFERED PRICE: Rs. 2,968
  • View Details
Get extra Rs. 445 off
USE CODE: COUPON10

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details