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Acceleration of a particle moving along a straight line is a function of velocity as a=2√v. At t=2, its velocity is v=16m/s. Its velocity at t=3 will be?

Acceleration of a particle moving along a straight line is a function of velocity as a=2√v. At t=2, its velocity is v=16m/s. Its velocity at t=3 will be?

Grade:11

2 Answers

Surodeep Sheth
28 Points
6 years ago
We havea=2√v
=>dv/dt =2√v
=>dv/√v = 2dt
 
integrating both sides,
2√v +C = 2t
given at t=2, v=16.
therefore we can find the value of C from the eqn.
C=-4
we have our final eq. as 2√v -4=2t
substituting t=3, we get v= √5 m/s
 
 
 
Surodeep Sheth
28 Points
6 years ago
** v is 25 m/s instead of sqrt 5 m/s sorry for that
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