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Amit Saxena Grade: upto college level
        A swimmer wishes to cross a 500 m wide river flowing at 5 km/h. His speed with respect to water is 3 km/h. (a) If he heads in a direction making an angle θ with the flow, find the time he takes to cross the river. (b) Find the shortest possible time to cross the river.
3 years ago

Answers : (1)

Navjyot Kalra
askIITians Faculty
654 Points
										Sol. a) The vertical component 3 sin θ takes him to opposite side.

Distance = 0.5 km, velocity = 3 sin θ km/h
Time = Distance/(Velocity ) = 0.5/(3 sin⁡θ ) hr
= 10/sin θ min.
b) Here vertical component of velocity i.e. 3 km/hr takes him to opposite side.
Time = Distance/Velocity = 0.5/3 = 0.16 hr
∴ 0.16 hr = 60 x 16 = 9.6 = 10 minute.
3 years ago
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