A projectile can have the same range for two angle of projection . if times of flight in two cases are t1 and t2 then velocity of projection of the projectile is

Question

Vikas TU · Answer

Dear Student,

let the velocity is u.
the 2 angle of projection are  and 90-
t1=2ucos/g
t2=2usin/g

t12+t22 = 4u2/g2 (since sin2+cos2 = 1)
=>u=(g/2)√(t1^2+t2^2 )

Cheers!!

Regards,

Vikas (B. Tech. 4^th year
Thapar University)

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A projectile can have the same range for two angle of projection . if times of flight in two cases are t1 and t2 then velocity of projection of the projectile is

A projectile can have the same range for two angle of projection . if times of flight in two cases are t1 and t2 then velocity of projection of the projectile is

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A projectile can have the same range for two angle of projection . if times of flight in two cases are t1 and t2 then velocity of projection of the projectile is

A projectile can have the same range for two angle of projection . if times of flight in two cases are t1 and t2 then velocity of projection of the projectile is

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