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a person moves on a circular track with radius 5 cm with a uniform speed 5 m/s. what is the magnitude of average acceleration of the particle over the time interval in which it completes one revolution?

a person moves on a circular track with radius 5 cm with a uniform speed 5 m/s. what is the magnitude of average acceleration of the particle over the time interval in which it completes one revolution?

Grade:11

3 Answers

Gaura
14 Points
6 years ago
As the speed is uniform so magnitude of average acceleration is 0 but cause direction changes constantly so the circular motion is said to be accelerated otherwise magnitude is null due to uniform s speed I.e. 2*π*5=31.4 m/s
Gaura
14 Points
6 years ago
Sorry the speed is 5m/sec as per the question and the above is missing written as speed please ignore at once
Gaura
14 Points
6 years ago
And time taken is( 2*π*0. 05)/5 that is equal to speed upon distance equals time that is 0.0628 radius is given in cm changing it to m =0.05m

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