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`        A particle starts from rest with uniform acceleration a. Its velocity after n seconds is v. the displacement of the particle in the last two seconds is.....`
2 years ago

erra akhil
208 Points
```										Dear Pranjal,v = u + a t -----eqn.1v-final velocityu-initial velocitya-accelerationt-time takenlet the velocity of the particle be v` just two seconds before which means t=(n-2) secondsSince initial velocity=0.on applying eq.1,v`=0+a(n-2)Now,S = u t + (1/2) a t2So the displacement in the last two seconds ishere the velocity before two seconds as found above is {(n-2)a} which becomes initial velocity for last 2 seconds and time is 2 seconds because we want displacement for last 2 secondsS = {a (n-2) } 2 + (½) a (22)S = 2 a (n-2) + 2aS= 2an-2aS= 2a(n-1) for last two seconds.
```
2 years ago
erra akhil
208 Points
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2 years ago
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