a particle of mass m strikes elastically on a wall with velocity v at an angle 60 degree from the wall then magnitude of change in moentum of ball along the wall is??

Question

Arun · Answer

Since momentum is vector quantity
so momentum toward the wall=mvcos30=mv√3/2
and momentum of ball while going back=-mv√3/2 since momentum remains conserved but direction is opposite
Momentum change=mv√3/2-(-mv√3/2)
2mv√3/2=mv√3

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a particle of mass m strikes elastically on a wall with velocity v at an angle 60 degree from the wall then magnitude of change in moentum of ball along the wall is??

a particle of mass m strikes elastically on a wall with velocity v at an angle 60 degree from the wall then magnitude of change in moentum of ball along the wall is??

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a particle of mass m strikes elastically on a wall with velocity v at an angle 60 degree from the wall then magnitude of change in moentum of ball along the wall is??

a particle of mass m strikes elastically on a wall with velocity v at an angle 60 degree from the wall then magnitude of change in moentum of ball along the wall is??

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