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A particle of mass M is equal to 3 kilogram is projected at angle of 45 degree with the horizontal with a speed of 20 root 2 metre per second. The angular momentum of the particle at the highest point of trajectory about the horizontal Axis passing through the origin and perpendicular to the plane of motion is

A particle of mass M is equal to 3 kilogram is projected at angle of 45 degree with the horizontal with a speed of 20 root 2 metre per second. The angular momentum of the particle at the highest point of trajectory about the horizontal Axis passing through the origin and perpendicular to the plane of motion is

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Grade:12

1 Answers

Vikas TU
14149 Points
6 years ago
Angle = 45 degree
          Velocity = 20√2 m/sec
Velocity along horizontal (vx) = v cos 45o
                                                =20√2/√2
                                                = 20 m/sec
Mass(M) = 3 kg
Momentum = mass * velocity
                   = 3* 20
                   = 60 kgm/sec

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