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a particle is projected vertically upwards and it reaches the maximum height H in T seconds. The height of particle at any time t will be? options: H-g(t-T)^2 g(t-T)^ 2 H-1/2g(t-T)^2 g /2(t-T)^2

a particle is projected vertically upwards and it reaches the maximum height H in T seconds. The height of particle at any time t will be?

options:

H-g(t-T)^2

g(t-T)^2

H-1/2g(t-T)^2

g/2(t-T)^2

Grade:11

1 Answers

Danyal Shahid shamsi
13 Points
6 years ago
The answer should be H -1/2g(t-T)^2Consider the body falling down. As both portions of motion of body are symmetrical. It should fall a certain distance in (t-T) time( the time it takes to attain maximum height when it is at the height reached by it in time interval t). so the height above the ground is H-(distance fallen in t time interval)

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