A particle is projected vertically up from top of tower with velocity 10m/s. It reaches a ground in 5 sec. Finda. Height of the towerb. Sticking velocity at groundc. Distance traversed by particled. Average speed and average velocity of particle

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Jigisha Joshi · Answer

distance traversed =85 m/sAvg speed =85/5=17m/sAvg velocity=75/5=15m/sHeight of the tower =S=ut-1/2gt×t=10×5-1/2×10×5×5=50-125=-75mStriking ground velocity=u-gt=10-10×50=-40m/s

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A particle is projected vertically up from top of tower with velocity 10m/s. It reaches a ground in 5 sec. Finda. Height of the towerb. Sticking velocity at groundc. Distance traversed by particled. Average speed and average velocity of particle

A particle is projected vertically up from top of tower with velocity 10m/s. It reaches a ground in 5 sec. Finda. Height of the towerb. Sticking velocity at groundc. Distance traversed by particled. Average speed and average velocity of particle

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A particle is projected vertically up from top of tower with velocity 10m/s. It reaches a ground in 5 sec. Finda. Height of the towerb. Sticking velocity at groundc. Distance traversed by particled. Average speed and average velocity of particle

A particle is projected vertically up from top of tower with velocity 10m/s. It reaches a ground in 5 sec. Finda. Height of the towerb. Sticking velocity at groundc. Distance traversed by particled. Average speed and average velocity of particle

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