A particle is moving along a straight line such that its acceleration can be given as a=3-4t, where t is in second. At t=0, its velocity is v=2m/s. Distance travelled by particle in 3 s is

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Arun · Answer

a = 3 -4t Hence dv = a.dt dv = (3-4t) dt On integrating v = 3t - 2t² +c But at t= 0, v =2 hence C = 2 Now ds = v dt On integrating S = -(2/3)t³ +(3/2) t² +2t Hence Distance travelled in 3 sec put t = 3 S = -18 +13.5 +6 S = 1.5 m

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A particle is moving along a straight line such that its acceleration can be given as a=3-4t, where t is in second. At t=0, its velocity is v=2m/s. Distance travelled by particle in 3 s is

A particle is moving along a straight line such that its acceleration can be given as a=3-4t, where t is in second. At t=0, its velocity is v=2m/s. Distance travelled by particle in 3 s is

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A particle is moving along a straight line such that its acceleration can be given as a=3-4t, where t is in second. At t=0, its velocity is v=2m/s. Distance travelled by particle in 3 s is

A particle is moving along a straight line such that its acceleration can be given as a=3-4t, where t is in second. At t=0, its velocity is v=2m/s. Distance travelled by particle in 3 s is

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