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Simran Bhatia Grade: 11
        A particle executes simple harmonic motion with an amplitude of 10 cm. At what distance from the mean position are the kinetic and potential energies equal?
3 years ago

Answers : (1)

Aditi Chauhan
askIITians Faculty
396 Points
										Sol. . r = 10cm

Because, K.E. = P.E.
So (1/2) m ω2 (r2– y2) = (1/2) m ω2y2
r2 – y2 = y2 ⇒ 2y2 = r2 ⇒ y = r/√2 = 10/√2 = 5√2 cm form the mean position
3 years ago
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