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Radhika Batra Grade: 11
        A mass of 6 × 1024 kg (equal to the mass of the earth) is to be compressed in a sphere in such a way that the escape velocity from its surface is 3 × 108 m s-1. What should be the radius of the sphere?
3 years ago

Answers : (1)

Navjyot Kalra
askIITians Faculty
654 Points
										Sol. The man of the sphere = 6 × 10^24 kg.

Escape velocity = 3 × 10^8 m/s
V base c = √2GM/R
Or R = 2GM/V base c^2
= 2 * 6.67 * 10^-11 * 6 * 10^24/(3 * 10^8)^2 = 80.02/9 × 10^–3 = 8.89× 10^–3 m = 9 mm.
3 years ago
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