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a man of mass 50 kg stands on a frame of mass 30 kg .he is pulled on a light rope which passes over a pulley . the other enf of the rope is attached to the frame .for the system to be in equilibrium what forced the man must exert on the rope

a man of mass 50 kg stands on a frame of mass 30 kg .he is pulled on a light rope which passes over a pulley . the other enf of the rope is attached to the frame .for the system to be in equilibrium what forced the man must exert on the rope

Grade:12

1 Answers

Shubham Kamleshbhai Patel
59 Points
8 years ago
According to the question, the tension in the string is equal to the net weight of the frame.
Also given that the system is in equilibrium,
T = [mass of the man + mass of the string] x g
   = [30 + 50] x 10
   = 800N
 
THUS THE FORCE EXERTED BY THE MAN ON THE ROPE IN A SYSTEM TO BE IN EQULIBRIUM IS 800N

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