A drop of water of volume V is pressed between two glass plates so as to spread in an area A. If T is the surface tension then the normal force required to separate the glass plates is ?

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Prashant · Answer

Normal force required will be = 2*(Surface Tension of liquid)*(Area)²/(Volume of liquid) aka N = 2TA²/V i found this in a book

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A drop of water of volume V is pressed between two glass plates so as to spread in an area A. If T is the surface tension then the normal force required to separate the glass plates is ?

A drop of water of volume V is pressed between two glass plates so as to spread in an area A. If T is the surface tension then the normal force required to separate the glass plates is ?

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A drop of water of volume V is pressed between two glass plates so as to spread in an area A. If T is the surface tension then the normal force required to separate the glass plates is ?

A drop of water of volume V is pressed between two glass plates so as to spread in an area A. If T is the surface tension then the normal force required to separate the glass plates is ?

1 Answers

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