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A body of mass ‘m’ is joined to a very heavy body by a light string passing over a light pulley.Both bodies are free to move.Total downward force on the pulley? Ans.4mg

A body of mass ‘m’ is joined to a very heavy body by a light string passing over a light pulley.Both bodies are free to move.Total downward force on the pulley?
 
Ans.4mg

Grade:12

4 Answers

Sumit Majumdar IIT Delhi
askIITians Faculty 137 Points
9 years ago
Dear student,
Please tell us the mass of the heavy body else we cannot find the net downward force on the pulley. The reason we need the mass of the heavier body as well because the net force would be equal to the tension and that would depend on the masses of both the bodies.
Regards
Sumit
Visisht
22 Points
9 years ago
Yes,but the answer given was 4mg....I doubt the answer because ‘m’ is the small mass and how the tension can be in small mass terms when it is given that the other body is a very heavy mass?
shashi K Sharma
46 Points
9 years ago
The question is correct and involves limit taking,Let the masses be m1 and m2,, (m1
Just do remember the tension in either of the string connecting the masses is
2(m1)(m2)g/(m1+m2)
divide the numerator and denominator by m2 and use the concept that m1/m2 tends to zero
you’ll get the answer as 2mg as tension on either side and hence 4mg as tension in string supporting pulley.
where m= mass of lighter block.
shashi K Sharma
46 Points
9 years ago
Also the downward force is 2(T) i.e. 4mg
Done.

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