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A body of mass M as shown in figure with a small disc m placed on it rests on a smooth horizontal plane. The disc is set in motion in horizontal direction with velocity v. To what height relative to initial level will the disc rise after breaking off the body M? There is no friction in environment.

A body of mass M as shown in figure with a small disc m placed on it rests on a smooth horizontal plane. The disc is set in motion in horizontal direction with velocity v. To what height relative to initial level will the disc rise after breaking off the body M? There is no friction in environment.

Grade:11

2 Answers

Naredra gandhi
13 Points
6 years ago
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Arnab Mahapatra
26 Points
5 years ago
The initial kinetic energy of the system=mv2/2
After collision the energy is distributed in the the inverse of mass ratio of the two bodies
That isthe body with less mass will gain more energy
Now, assuming it to be an elastic collision:
M/(M+m)*(initial kinetic energy)=mgh
M/(m+M)*(mv2)/2=mgh
Solving them we will get
h=Mv2/2g(M+m)

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