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A ball is projected from the top of tower with velocity of 5 m/s and at an angle of 53° what is the velocity when it will be at height 0.45 from the top... plzz explain this fully thank you

A ball is projected from the top of tower with velocity of 5 m/s and at an angle of 53° what is the velocity when it will be at height 0.45 from the top... plzz explain this fully thank you

Grade:11

1 Answers

Suryansh Mishra
24 Points
6 years ago
Hello,please do specify the angle made, is with horizontal or vertical.And whatever may be the case.Try to solve it by taking its vector components.If angle made is with the horizontal then y component will be (v sin angle) which in this case is 5 sin53.as we know sin53 is 4/5 we get the horizontal component to be 4 m per second.now I think u will be able to do it. I would have completed it but what is the frame of reference of the given height. I mean it`s measured from max height or ground.That`s it was it helpful.

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