MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Simran Bhatia Grade: 11
        A 250 g block slides on a rough horizontal table. Find the work done by the frictional force in bringing the block to rest if it is initially moving at a speed of 40 cm/s. If the friction coefficient between the table and the block is 0.1, how far does the block move before coming to rest?
3 years ago

Answers : (1)

Deepak Patra
askIITians Faculty
474 Points
										Sol. . Given, m = 25 base o g = 0.250kg,

u = 40 cm/sec = 0.4m/sec
μ = 0.1, v=0
Here, μ R = ma {where, a = deceleration}
a = μR/m = μmg/m = μg = 0.1 * 9.8 = 0.98 m/sec^2
S = v^2 – u^2/2a = 0.082m = 8.2 cm
Again, work done against friction is given by
- W = μ RS cos θ
= 0.1 * 2.5 * 0.082 * 1 (θ = 0°) = 0.02 J
⇒ W = - 0.02 J
3 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: Rs. 2,756
  • View Details
  • Complete Physics Course - Class 11
  • OFFERED PRICE: Rs. 2,968
  • View Details

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details