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`        A 250 g block slides on a rough horizontal table. Find the work done by the frictional force in bringing the block to rest if it is initially moving at a speed of 40 cm/s. If the friction coefficient between the table and the block is 0.1, how far does the block move before coming to rest?`
3 years ago

Deepak Patra
474 Points
```										Sol. . Given, m = 25 base o g = 0.250kg,
u = 40 cm/sec = 0.4m/sec
μ = 0.1, v=0
Here, μ R = ma {where, a = deceleration}
a = μR/m = μmg/m = μg = 0.1 * 9.8 = 0.98 m/sec^2
S = v^2 – u^2/2a = 0.082m = 8.2 cm
Again, work done against friction is given by
- W = μ RS cos θ
= 0.1 * 2.5 * 0.082 * 1 (θ = 0°) = 0.02 J
⇒ W = - 0.02 J

```
3 years ago
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