0

Guest

Courses New

4 A bead of mass m is located on a parabolic wire with its axis vertical and vertex directed towards downward as in figure and whose equation is x² = ay. If the coefficient of friction is µ, the highest distance above the x-axis at which the particle will be in equilibrium is (a) µa (b) µ²a (c)1/4 µ^2 g (d)1/2µ^ g

4 A bead of mass m is located on a parabolic wire with its axis vertical and vertex directed towards downward as in figure and whose equation

is x² = ay. If the coefficient of friction is µ, the highest distance above
the x-axis at which the particle will be in equilibrium is

(a) µa (b) µ²a (c)1/4 µ^2 g (d)1/2µ^ g

Grade:11

1 Answers

Vikas TU
14149 Points
7 years ago
tangent at any x distance would be => tanthetha =2x/a
Now
friction = umgcosthetha
Balancing friction with mg*sin(thetha) we get,
ucosthetha = sinthetha
or
tan(thetha) = u
2x/a = u
x = au/2
The highest point would be,
y = (au/2)^2/a => a^2u^2/4a => au^2/4 

Think You Can Provide A Better Answer ?

Other Related Questions on Mechanics

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More