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Dear Aditya Nijampurkar,
Ans:- It is clear that the trajectory is a circle iff the bottommost point is in stable condition i.e it is not sleepping.
Next, the CM falls a distance R. as there is no sleepping hence this entire energy converts into rotational K.E hence
1/3M (2R)²W²=MgR
Hence W=√(4g/3R)
Hence V=2WR=2√(4gR/3)
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Regards,
Askiitians ExpertsSoumyajit Das IIT Kharagpur
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