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A man pushes a cylinder of mass m1 with the help of a plank of mass m2. There is no slipping at any contact. The horizontal component of the force applied by the man is F.Find

a)the accelerations of the plank and the centre of mass of the cylinder,and

b)the magnitudes and directions of frictional force at contact points.

6 years ago


Answers : (1)


Dear Bharath Devasani,

Ans:- Now draw the FBD of two bodies.

The cylinder in the bottom will have the following set of forces 

f1=force of friction between the two bodies and is towards right for the cylinder and towards left for the plank. 

f2=force of friction between the ground and the cylinder and is towards left.

F=applied horizontal force on the plank

a1= Acceleration of the plank towards the right

a= Acc of the cylinder towards right

ß= Angular Acc of the cylinder

Then the eqns  of motion are

F-f1=M2 a1.........................(1)

f1 - f2=M1 a........................(2)

(f1+f2)r=Iβ...........................(3) (where I= momont of inertia= 1/2 M2 r²)

And the conditions of non slleeping are

a1=a+ βr..................(4)(At the top cotact of two bodies)

a2=βr..............(5)(At the contact of the cylinder and the ground)

Solving these Eqsns we get



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6 years ago

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