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				   the time period of the  particle executing simple harmonic motion is 8 sec.At T=0 it is at mean position.the ratio of the distance covered by the particle in 1st sec to 2nd sec is

6 years ago


Answers : (1)

										Dear jauneet

let the equation of motion is

X =Asin(2px/8)

in first second X1 =Asin(p/4)
in 2 sec X2 =Asin(p/2)
so 2nd sec distance covered = X2 -X1

x1 /(X2 -X1) = Asin(p/4)/[Asin(p/2) -Asin(p/4)]
=1/(v2 -1)

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