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jauneet singh Grade: 12
        the time period of the  particle executing simple harmonic motion is 8 sec.At T=0 it is at mean position.the ratio of the distance covered by the particle in 1st sec to 2nd sec is
7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										Dear jauneet


let the equation of motion is

X =Asin(2px/8)

in first second X1 =Asin(p/4)
in 2 sec X2 =Asin(p/2)
so 2nd sec distance covered = X2 -X1

x1 /(X2 -X1) = Asin(p/4)/[Asin(p/2) -Asin(p/4)]
=1/(v2 -1)

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Badiuddin
7 years ago
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