a man of mass50 kg is standing on a 100kg plank kept on a fictionless horizontal floor. initially both are at rest if man starst walking on the plank with speed 6m/s towards right relative to the plank then amount of muscle energy spent by the man is!!????

Question

Chetan Mandayam Nayakar · Answer

from principle of conservation of momentum, man and plank move in opposite directions w.r.t. floor with speeds v and u respectively. conservation of momentum implies 50v=100u,v=2u, v+u=6, therefore u=2m/s and v= 4m/s,

Energy= (50/2)4² +(100/2)2² =600 Joule

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Gaurav · Answer

Hello Student Number of Photons emitted , n = 2.5 x 10 15 Duration of Source , T = 2 X 10 -9 s Energy of Source . E = nhv = nh/T = 8.3 X 10 -10 J

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a man of mass50 kg is standing on a 100kg plank kept on a fictionless horizontal floor. initially both are at rest if man starst walking on the plank with speed 6m/s towards right relative to the plank then amount of muscle energy spent by the man is!!????

a man of mass50 kg is standing on a 100kg plank kept on a fictionless horizontal floor. initially both are at rest if man starst walking on the plank with speed 6m/s towards right relative to the plank then amount of muscle energy spent by the man is!!????

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a man of mass50 kg is standing on a 100kg plank kept on a fictionless horizontal floor. initially both are at rest if man starst walking on the plank with speed 6m/s towards right relative to the plank then amount of muscle energy spent by the man is!!????

a man of mass50 kg is standing on a 100kg plank kept on a fictionless horizontal floor. initially both are at rest if man starst walking on the plank with speed 6m/s towards right relative to the plank then amount of muscle energy spent by the man is!!????

2 Answers

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