Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
a particle is attached to the end of the vertical rod with the other end hinged.the particle is now imparted velocity such that it completes vertical revolution.the rod is inclined at the angle sin^-(1/x) with the horizantal when the net force on the particle is horizantal.what is value of x
let l be the length of the rod. At the top of the circle, velocity =zero. thus when angle =arcsin(x), KE =mgl(1+x)=(mv^2)/2
v^2=2gl(1+x). NET FORCE ON PARTICLE IS ZERO WHEN VERTICAL COMPONENT OF CENTRIPETAL FORCE BALANCES GRAVITY.
v2/l =2g(1+x),v2x/l=2gx(1+x), Now we thus have 2gx(1+x)=g, x=(√3-1)/2
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !