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What is the method of obtaining the moment of inertia of a cylinder of mass M and radius R and length L through
(i) the centre perpendicular to the length
(ii) end faces and perpendicular to the length.
Please explain.
Dear Hinan ali
we know that
Iz= mr2/2
and Ix + Iy =Iz
by symmetry Ix =Iy
so Ix =Iz/2
=mr2/4
and from parallel axix theorem Ix' = Ix + mx2
so Ix' = Ix + mL2/4
=mr2/4 + mL2/4
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