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```        a clyinderical hall has an smooth horizantal floor.a ball is projected along the floor from a point on the wall in an directiom making an angle x with the radius through the point.the ball return 2 the inital points after two impacts with the wallif the coefficent of restution is e,then tan^2x is
ans is e^3/e^2+e+1
how can i get this ans```
7 years ago

147 Points
```										Dear jimmyu
let after impact angel made by ball with the radius  is y
and after second impact angel made by ball with the radius  is z
so 2x+2y+2z =180
or  x+y+z = 90  ........................1
at the first point where ball made first  impact
vsinx = v1siny
and  e = v1cosy /vcosx

so  e = tanx/tay    or  tany = tanx/e  ...........2
similerly for  second impact
tanz = tany/e  or   tanz = tanx /e2 ............3

from equation 1
(90-x) = y+z
or  tan(90-x) = tany + tanz /(1-tanytanz)
1/tanx = (tany +  tanz)/(1-tanytanz)

put value of  tany and tanz from  equation 2and 3
tan2x = e3/(e2 +e  +1)
Please feel free to post as many doubts on our discussion  forum as you can. If you find any question Difficult to understand - post it here and we  will get you the answer and detailed solution very quickly.   We are all IITians and here to help you in your IIT JEE preparation.   All the best.   Regards, Askiitians Experts Badiuddin
```
7 years ago
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