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Chandan Das Grade: Upto college level
```        1.The length of of a seconds hand in a watch is 1cm.The change in velocity of its tip in 15s is what?
2.A particle is projected vertically upwards and reaches the maxm. ht. H in time T.The ht. of a particle at any time t will be what?```
7 years ago

147 Points
```										Dear Chandan Das
speed of tip of second hand is constant =2∏*1/60  cm/sec
=∏/30  cm/sec
so in 15 sec it will rotate by an angel 90 degree
initial velocity = ∏/30 i
final velocity = ∏/30(-j)
change in velocity = | ∏/30(-j)  - ∏/30 i|
=∏√2/30  cm/sec

Please feel free to post as many doubts on our discussion forum as you can.If you find any question Difficult to understand - post it here and we will get you the answer and detailed  solution very  quickly. We are all IITians and here to help you in your IIT JEE preparation.All the best. Regards,Askiitians ExpertsBadiuddin
```
7 years ago
Nehal Wani
21 Points
```										Ans 2: Max Height: u^2sin^?/2g =  H
usin?/g     =  T
Displacement at any time t = xtan?-(1/2)gx^2/(u^2cos^2?)
Replace x with ucos?t      : utsin?-(1/2)gt^2
=2Ht/T-(1/2)gt^2
```
7 years ago
Nehal Wani
21 Points
```										Max Height Attained : H = (u2sin2θ)/2g      ½

Time Taken For Achieving Max. Height : T = usinθ/g
Displacement At Any time t: xtanθ-½gx2/(u2cos2θ)
Replace x with ucosθt : utsinθ-½gt2
= 2Ht/T-½gt2

```
7 years ago
Meera
17 Points
```										What is the answer jjfhhvhkbdriknbvfdtuinnnbbnnhnnnfdchjnnmnnbvfgghjkkkjjfhhvhkbdriknbvfdtuinnnbbnnnkyhjnnnnkkkkkrkknbvfgghjkkk and zoology notes and put
```
2 months ago
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