1. The 2 ends of a spring balance are pulled each by a force of 10 kgwt. What will be the reading of the spring?

2. How much below the surface of the earth does the acceleration due to gravity is 10% of its value at the earth's surface ? R = 6400 km = Radius of earth.

Question

1. The 2 ends of a spring balance are pulled each by a force of 10 kgwt. What will be the reading of the spring?

2. How much below the surface of the earth does the acceleration due to gravity is 10% of its value at the earth's surface ? R = 6400 km = Radius of earth.

Nehal Wani · Answer

Ans 1: T / =2T Therefore, reading of spring:20N Ans 2: g d =g s (1-d/R) g s /10=g s (1-d/R) d=9R/10=5760km

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1. The 2 ends of a spring balance are pulled each by a force of 10 kgwt. What will be the reading of the spring? 2. How much below the surface of the earth does the acceleration due to gravity is 10% of its value at the earth's surface ? R = 6400 km = Radius of earth.

1. The 2 ends of a spring balance are pulled each by a force of 10 kgwt. What will be the reading of the spring?

2. How much below the surface of the earth does the acceleration due to gravity is 10% of its value at the earth's surface ? R = 6400 km = Radius of earth.

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1. The 2 ends of a spring balance are pulled each by a force of 10 kgwt. What will be the reading of the spring? 2. How much below the surface of the earth does the acceleration due to gravity is 10% of its value at the earth's surface ? R = 6400 km = Radius of earth.

1. The 2 ends of a spring balance are pulled each by a force of 10 kgwt. What will be the reading of the spring? 2. How much below the surface of the earth does the acceleration due to gravity is 10% of its value at the earth's surface ? R = 6400 km = Radius of earth.

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1. The 2 ends of a spring balance are pulled each by a force of 10 kgwt. What will be the reading of the spring?

2. How much below the surface of the earth does the acceleration due to gravity is 10% of its value at the earth's surface ? R = 6400 km = Radius of earth.