Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        a particle moves with a decreasing speed along the circle of radius r so that at any moment its tang and centripetal acc are equal in magnitude.at t=0,its speed is u.plz time after which speed reduce to 0`
7 years ago

147 Points
```										Dear jauneet
at any instant tangential acceleraion is given by = dV/dt
but this is equal to centripital acceleation which is given as = mV2/r
so   dV/dt = V2/r
dV/V2 = 1/r dt
∫dV/V2 =∫ 1/r dt
-1/V = 1t/r + C
apply condition at t=0 V=u
so C=-1/c
equation become   -1/V = 1t/r + -1/u
1/V = 1/u  + t/r
1/V =(r+tu)/ur
V=ur/(r+tu)
so clearly after infinite time particle will come to rest
Please feel free to post as many doubts on our discussion forum as you can.If you find any question Difficult to understand - post it here and we will get you the answer and detailed  solution very  quickly. We are all IITians and here to help you in your IIT JEE preparation.All the best. Regards,Askiitians ExpertsBadiuddin

```
7 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »
• Complete Physics Course - Class 12
• OFFERED PRICE: Rs. 2,756
• View Details
• Complete Physics Course - Class 11
• OFFERED PRICE: Rs. 2,968
• View Details