MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: R

There are no items in this cart.
Continue Shopping
Menu
sohan singh singh Grade: 12
        


Find the minimum distance between the curves y^2 = x-1 and x^2 = y-1                                   please give detail  solution


7 years ago

Answers : (1)

Ramesh V
70 Points
										

Interesting problem.

I found the distance is from point ( 5/4 , 1/2 ) to point ( 1/2, 5/4 )


Note the symmetry of the curve.


So the minimum distance is (3/4) * sqrt (2 ) which is approximately 1.06


I will come back with more details.


My general approach is this:


let the points be (x1,y1) and (x2,y2 )


Find the distance square


d^2 = (x1 -x2) ^2 + (y1 -y2)^2


eliminate (y1, y2 ) from d^2


set ( d (d^2) / dx1 =0 , d (d^2) /dx2 =0 )


solve for (x1,x2)


--


regards


Ran\mesh

7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: R 2,600
  • View Details
Get extra R 2,500 off
USE CODE: SSP11
  • Complete Physics Course - Class 11
  • OFFERED PRICE: R 2,800
  • View Details
Get extra R 2,500 off
USE CODE: SSP11

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details