Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
sohan singh singh Grade: 12
```
Find the minimum distance between the curves y^2 = x-1 and x^2 = y-1                                   please give detail  solution
```
7 years ago

## Answers : (1)

Ramesh V
70 Points
```										Interesting problem. I found the distance is from point ( 5/4 , 1/2 ) to point ( 1/2, 5/4 )   Note the symmetry of the curve.  So the minimum distance is (3/4) * sqrt (2 ) which is approximately 1.06  I will come back with more details.  My general approach is this:   let the points be (x1,y1) and (x2,y2 )   Find the distance square   d^2 = (x1 -x2) ^2 + (y1 -y2)^2   eliminate (y1, y2 ) from d^2   set ( d (d^2)  / dx1 =0 , d (d^2) /dx2 =0 )   solve for (x1,x2)
--
regards
Ran\mesh
```
7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on Mechanics

View all Questions »
• Complete Physics Course - Class 12
• OFFERED PRICE: Rs. 2,756
• View Details
• Complete Physics Course - Class 11
• OFFERED PRICE: Rs. 2,968
• View Details