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`        The relation between time t and distance x is t = ax^2 + bx, where a and b are positive constants. Its acceleration is?`
7 years ago

147 Points
```										Dear Vishrant
t = ax^2 + bx
differentiate w.r.t t
1= 2ax dx/dt + b dx/dt
1= (2ax+b)dx/dt
dx/dt = 1/(2ax+b)
again differentiate
a= -1/(2ax+b)2   * 2a/(2ax+b)
a = -2a/(2ax+b)3
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7 years ago
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