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vardaan kumar Grade: 11
        

A BODY OF MASS 10kg IS BEING ACTED APON BY A FORCE 3t2 AND AN OPPOSING CONSTANT FORCE OF 32N. THE INITIAL SPEED IS 10m/s THE VELOCITY OF BODY AFTER 5s IS=?

7 years ago

Answers : (1)

Ramesh V
70 Points
										

The forces on body are 32 N (opposing) and 3t2 ( in same dirn) along with ma ( driving force )


so, 32 = 3t2 + ma


32 = 3t2 + 10a


also V = u + at


at t = 5 from, both equations


V = 10 + (-4.3)*5


   = -11.5 m/sec


It looks like body is decelerating, so it comes to rest after some if 32N is opposing force even before 5 seconds


P.S: I think thr is some wrong info in question


     --


regards


Ramesh

7 years ago
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