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ANGLE BTW (i+j+k) and (i+j) is x.THEN 2SEC2
x is
Dear vardana
ANGLE BTW (i+j+k) and (i+j) is x
cosx =(i+j+k).(i+j)/|i+j+k||i+j|
=2/√3 √2
=√2/√3
secx =√3/√2
2sec2x =3
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