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one end of uniform rod of mass m and length l is clamped.the rod lies on smooth horizontal surface and rotates about its clamped endat an uniform angular velocity w.what is the horizontal component of force exerted by clamp on rod?
thank you for puting up this que.
may be -mw2r-centripetal force
Dear Apoorv Jain
In rotational motion the angular velocity is constant for all points.Consider a small piece of mass "dm" then force is dF.
dF=(dm)xw2
L length→M mass
for small portion dx→?
=Mdx/L
now F=∫(M/L)w2 x dx between limits 0 to L.
Finally F=(1/2)MLw2
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