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Mainak Chakraborty Grade: Upto college level
        

9.     A solid sphere of mass M, radius R and having moment of inertia about an axis passing through the centre of mass as I, is recast into a disc of thickness t, whose moment of inertia about an axis passing through its edge and perpendicular to its plane remains I. Then, radius of the disc will be


        (A) 2R/√15


        (B) R√(2/15)


        (C) 4R/√15


        (D) R/4

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear Mainak


moment of inertia of solid sphere I =2/5 MR2


mass will remain conserve


 let the new radius is R1


so I = MR12/2 + MR12


       =3/2 MR12


 


so 3/2 MR12 =2/5 MR2


    R1 =2R/√15


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Badiuddin

7 years ago
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