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`        a boy whirls the stone in horizontal circle of radius 1.5m....at a height of 2 m,,,,,above the ground..the string breaks and the stone flies off horizontally and strikes the ground after travellin a hori distance of 10m,,,,find its centripeal acceleration..`
7 years ago

147 Points
```										Dear shivanshi
It is a question of projectile motion
let the horizontal velocity of stone when string breaks is =V
verticale velocity is zero
let  time taken to reach the ground is t
equation for verticle motion
h=1/2gt2
2=1/2 * 10 * t2
t= √.4
so equation for horizontal motion
S =Vt
10 = V *√.4
V= 15.81 m/sec
so centripital acceleration = V2/r
= (15.81)2 /1.5
=166.64 m/sec2
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7 years ago
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