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shivanshi asthana Grade: 11
        

a boy whirls the stone in horizontal circle of radius 1.5m....at a height of 2 m,,,,,above the ground..the string breaks and the stone flies off horizontally and strikes the ground after travellin a hori distance of 10m,,,,find its centripeal acceleration..

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear shivanshi


It is a question of projectile motion


let the horizontal velocity of stone when string breaks is =V


verticale velocity is zero


let  time taken to reach the ground is t


equation for verticle motion


 h=1/2gt2


2=1/2 * 10 * t2


t= √.4


so equation for horizontal motion


S =Vt


10 = V *√.4


V= 15.81 m/sec


so centripital acceleration = V2/r


                                      = (15.81)2 /1.5


                                      =166.64 m/sec2


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7 years ago
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