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a particle starts from t=0 with a velocity of 8j and moves inthe xy plane with a constant acceleraton of 4i+2j......at the moment when its x coordinate is 29m,what is its speed?y coordinate?
Dear shivanshi
ux = 0
uy= 8 m/sec
ax = 4 m/sec2
ay = 2 m/sec2
use formula Sx= ux t + 1/2 ax t2
29 = 0 + 1/2 *4 *t2
t= √(29/2) sec
Vx = Ux + ax t
= 4√(29/2)
Vy =Uv + ay t
=8 + 2√(29/2)
speed =[Vx2 +Vy2]1/2
y co ordinate Sy=Uy t + 1/2 ayt2
=8√(29/2) +29/2
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