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shivanshi asthana Grade: 11
        

a particle starts from t=0 with a velocity of 8j and moves inthe xy plane with a constant acceleraton of 4i+2j......at the moment when its x coordinate is 29m,what is its speed?y coordinate?

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear shivanshi


 ux = 0


uy= 8 m/sec


ax = 4 m/sec2


ay = 2 m/sec2




 use formula  Sx= ux t + 1/2 ax t2


                      29 = 0 + 1/2 *4 *t2


                     t= √(29/2)  sec


   Vx = Ux  + ax t


        = 4√(29/2)


 Vy =Uv + ay t


      =8 + 2√(29/2)


speed  =[Vx2 +Vy2]1/2


y co ordinate Sy=Uy t + 1/2 ayt2


                            =8√(29/2)  +29/2


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Badiuddin


 

7 years ago
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