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shivanshi asthana Grade: 11
        

a 40kg girl and an 8.4 kg sled are connected and are on frictionless ice of a frozen lake,15 m apart and the girl exerts 5.2N on the rope...how far from the girl's position do they meet?

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear shivanshi


 


girl exerts 5.2N on the rope


so rope also exerts 5.2 N force on girl .and same force also exert ny rope at the other end to sled


acceleration of girl = 5.2/40  =.13 m/sec2


acceleration of sled = 5.2 /8.4 =.62 m/sec2


relative acceleration of girl w.r.t sld  =a = .62 + .13 =.75 m/sec2


let time taken to meet  is t


S=1/2 a t2


15 =1/2 * .75 * t2


 t2 =40


distance travel by girl in this time


S=1/2* 5.2/40 * 40


   =5.2/2 =2.6 m answer


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Badiuddin

7 years ago
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