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```				   for a womans volleyball the top of the net is 22.4 m above the ground.and the court measures 9m by 9m on each sideof the net.using a jump throwa player a player strikes the ball at a point 3m above the floor and a horizontal distance of 8m from the net.initial vel of the ball is horizontal.what min magnitude must the initial vel have so as to clear the net??
```

6 years ago

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```										Dear shivanshi
Hight of the net is 22.4 m
and it has given a horizontal velocity at a hight 3 m .then it will never cross the net.
I think question has some error check it and post agian.
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE  & AIEEE preparation. All the best. Regards,Askiitians ExpertsBadiuddin
```
6 years ago
```										Is the answer 20.32m/s
```
6 years ago
```										Dear Shivanshi,
When you get the solution please forward it to me. It wud be reeally kind of you.
Thanks
Shreyans
```
6 years ago

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