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`        A trolley was moving horizontally on a smooth ground with velocity v w.r.t earth. Suddenly a man starts running from the rear end of the trolley with a velocity (3/2) v w.r.t trolley. After reaching the other end, the man turns back and continues running with a velocity (3/2) v w.r.t the trolley in opposite direction. If the length of the trolley is L, find the displacement of the man w.r.t earth when he reaches the starting point of the trolley. Mass of the trolley is equals to the mass of the man.`
7 years ago

147 Points
```										Dear Sanchit
initial velocity of trolly = v
let when  start running then velocity of trolly become =v1
velocity of man with respect to earth = ( v1 + 3/2v)
conservation  of momentum
(m+m)v = mv1  + m(v1 + 3/2v)
v1 =v/4
time  taken by man to reach at the other end t1 = L /(3/2 v)
=2L/3v

when starts moving in backward direction let  velocity of trolly  =v2
then velocity of man w.r.t earth  = v2 -  3/2 v
conservation of momentum
(m+m)v = mv2  + m(v2 - 3/2  v)
v2 = 5v/4
time taken by man to reach at the initial  end t2 = L /(3/2 v)
=2L/3v
so distance moved by trolly  = V1 t1  + V2t2
=v/4 * 2L/3v   +  5v/4 *  2L/3v
=L
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```
7 years ago
Vikash Kumar Singh
30 Points
```										We have, L = length of the trolley.v = velocity of trolleyvelocity of man = 3v/2.Let,t = time taken by man to reach to other end of the trolley and come back to starting end of the trolley. Total distance travelled = 2 L.Now,velocity = distance/timeTherefore,3v/2=2L/t3v/2=2L/tTherefore,t=4L/3vt=4L/3v__________(1)But, in the same time, trolley has covered some distance wrt Earth.Let,d = distance covered by the trolley in time t.Therefore,v = d / tt = d/v ____________ (2)from (1) and (2),4L/3v=d/v4L/3v=d/vTherefore,d=4L/3d=4L/3Total distance covered by man wrt earth will be 2 L + 4L/3 = 10L/3.4L/3 is the distance covered by man w.r.t earth. As the man comes back to the original point, the `L` distance covered in forward direction cancels out.
```
one month ago
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