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neeraj pawar Grade: 12
        

a small particle of mass m atached with a light inextensible spring L is moving in a vertical circle .minimum velocity required for the particle to go around complete vertical circle at highest ponit is √gl.in the given case the particle is moving in complete vertical circle & ratio of it's maximum to minimum velocity is 2:1
What is the minimum velocity
a)4√gl/3
b)2√gl/3
c)√gl/3
d)3√gl/3

ans (B) 2√gl/3


 


6642-1738_6545_dd.jpg

7 years ago

Answers : (1)

Nagaraju Kandru
31 Points
										

 


In this problem, the given velocity(√gl ) is the minimum velocity required for the particle at its highest point to complete vertical circle.


Let, u & v be the velocity of the particle at its lowest and highest point respectively.


u : v = 2:1 => u = 2v.----------->(1)


according to work-energy theorem,


mg(2l) = (1/2)mu2 - (1/2)mv2 --------------->(2)


from eqns (1)& (2), we get v = (2/3)(√gl).


 


This is the minimum velocity of the particle in its complete circular motion in this present case.

7 years ago
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