Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```        Figure shows a small block of mass m kept at the left end of a larger block of mass M and length l.
The system can slide on a horizontal road. The system is started towards right with an intial velocity v. The friction coefficient between the road and the bigger block is µ and that between the blocks is µ/2.
Find the time elapsed before the smaller block separates from the bigger block.```
7 years ago

## Answers : (1)

147 Points
```										Dear jayesh

N1=mg
N2=(m+m)g
a1=-μ/2 N1/m
=-μg/2
a2=(μN1/2 -μN2)/M
=(μmg/2 -μ(m+m)g)/M
initial velocity of smaller block with respect to biggere =v-v =0
acceleration of smaller block w.r.t bigger = a1-a2
so smaller block sepeate
S=l =0*t +1/2 (a1-a2) t2
t2 =2l/(a1-a2)
put value of a1 and a2
and find t
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.

```
7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies

## Other Related Questions on Mechanics

View all Questions »
• Complete Physics Course - Class 12
• OFFERED PRICE: Rs. 2,756
• View Details
Get extra Rs. 551 off
USE CODE: CHEM20
• Complete Physics Course - Class 11
• OFFERED PRICE: Rs. 2,968
• View Details
Get extra Rs. 594 off
USE CODE: CHEM20