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Jayesh Arun Kadam Grade: 12
        

Find the acceleration of mass M in the situation of figure. The coefficient of friction between the two blocks is µ1 and that between the bigger block and the ground is µ2.

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7 years ago

Answers : (3)

Badiuddin askIITians.ismu Expert
147 Points
										

dear jayesh


let normal reaction between two block is N1 ,and the normal reaction between biggger block and ground in N2


for smaller block


so mg - T -μ1N1 =m2a.....1


 N1=ma .............2


 for bigger block


N2 =Mg +μ1N1 +T


   or  N2=Mg + mg-2ma (from equation 1).......3


and  T +T -N1 -μ2N2=Ma


       2T -ma -μ2(Mg +mg-2ma) =Ma ........4


put value of T from equation 1


2(mg -μ1ma-2ma) -ma -μ2(Mg +mg-2ma) =Ma


solve for a


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7 years ago
Faraz Nassar
11 Points
										
Why is N2= mg +u1N1 + T as u1N1 and T are in opposite direction to Mg? And why did we take 2T in the equation of M? 
8 months ago
Vineeth Chennabhoina
14 Points
										
N2 is the normal reaction force on the bigger block, it’s equal to the sum of it’s own weight, and u1N1 because the smaller as the smaller body goes down, it rubs against the bigger body, and the friction between them is u1 and the Normal reaction between them is due to the weight of the smaller body. And T because, do you see the upper pulley attached to the bigger body, that’s causing a tension T on the body.
 
And we’ve taken 2T in the equation because there’s two sets of ropes that have tention T in them, the top and the bottom, the vertical rope doesn’t have tension in it. That’s why we’ve taken 2T.
 
I hope that clarifies your doubts Faraz.
3 months ago
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