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pallavi pradeep bhardwaj Grade: 12
        

A heavy box of mass 20 kg is pulled on a horizontal surface.If the coefficient of kinetic friction between the box and the horizontal surface is 0.25 find the force of friction exerted by the horizontal forces on the box

7 years ago

Answers : (2)

Askiitians Expert Bharath-IITD
23 Points
										

Dear Pallavi,


The kinetic friction generated due the horizontal forces on the box is given by the formula Fk= μkmg = 0.25 * 20 * 9.8 N = 49N


 


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Adapa Bharath

7 years ago
Shankararama Sharma
35 Points
										

While in motion only the kinetic friction acts. f=uN.


                                                               f=umg


                                                                =0.25*20*9.8


                                                                =49N


so the friction exerted by the horizontal forces is 49N.

6 years ago
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