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sindhuja P Grade: 11
        

A particle of mass m is placed at rest on the top of a smooth wedge of mass M,which in turn is placed at rest on a smooth horizontal surface.If hbe the height of wedge and θ is the inclination,then the distance moved by the wedge as the particle reaches the foot of the wedge is ______________

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear sindhuja


there is no external horizontal force is acting on the system so center of mass will not move in x direction.


base of the wedge = hcotΘ


let the left lower  corner of wedge is origin and wedge move by x' distance ,and center of mass of wedge is at x1 distance from origin


so (mhcotΘ  +Mx1)/(m+M)  ={m(x'-hcotΘ) +M(x1+x')}/(m+M)


or  mhcotΘ  +Mx1  =m(x'-hcotΘ) +M(x1+x')


or 2mhcotΘ =(m+M)x'


 x'= 2mhcot/(m+M)


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Badiuddin


 

7 years ago
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