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`        A particle travels in a straight line such that for a short time 2s<t<6s, its motion is described by v=(4/a)m/s, where 'a' is in m/s2. If v=6m/s when t=2sec, determine the particle's acceleration when t=3 sec.`
7 years ago

147 Points
```										Dear Chilukuri
V=4/a
Va =4
V dv/dt =4
intigrate
V2/2 =4t +c1
V2 =8t +c
apply given condition
36 =16 +c
c= 20
so
V2 =8t +20
velocity at t=3 sec
V = √44
so acceleration  a=4/v  =4/√44
=2/√11 m/sec2
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the
```
7 years ago
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