MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Chilukuri Sai Kartik Grade: 12
        

A particle travels in a straight line such that for a short time 2s<t<6s, its motion is described by v=(4/a)m/s, where 'a' is in m/s2. If v=6m/s when t=2sec, determine the particle's acceleration when t=3 sec.

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear Chilukuri


V=4/a


Va =4


V dv/dt =4


intigrate


V2/2 =4t +c1


V2 =8t +c 


apply given condition


36 =16 +c


c= 20


so


V2 =8t +20 


velocity at t=3 sec


V = √44 


so acceleration  a=4/v  =4/√44


                                =2/√11 m/sec2


Please feel free to post as many doubts on our discussion forum as you can.
 If you find any question Difficult to understand - post it here and we will get you the


answer and detailed solution very quickly.
 We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.


 All the best.
 
Regards,
Askiitians Experts
Badiuddin

7 years ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies
  • Complete Physics Course - Class 12
  • OFFERED PRICE: Rs. 2,756
  • View Details
Get extra Rs. 551 off
USE CODE: CART20
  • Complete Physics Course - Class 11
  • OFFERED PRICE: Rs. 2,968
  • View Details
Get extra Rs. 594 off
USE CODE: CART20

Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details