Click to Chat

1800-2000-838

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        A point mass starts moving in straight line with const.acceleration. After time to,the acceleration changes its sign, remaining the same in magnitude. Determine the time t from the beginning of motion in which the point mass returns to the initial position?`
8 years ago

147 Points
```										Dear Chilukuri
after to  velocity of particle =ato

Distance travell in time to
S1 =0 +1/2 a to2
Time taken from from Point B to C in forward motion is
v=u -at
0=ato -at
t= to
same time willl take to come from point c to b
and from motion B to A  time take is
S1 = at0 + 1/2 a t2
1/2 a to2   = at0 + 1/2 a t2
solve for t
t = ( √2 -1 )to
so total time  t = to +to +to +( √2 -1 )to
=( √2 +2 )to

Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.
```
8 years ago
147 Points
```
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the
```
8 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Mechanics

View all Questions »
• Complete Physics Course - Class 12
• OFFERED PRICE: Rs. 2,756
• View Details
• Complete Physics Course - Class 11
• OFFERED PRICE: Rs. 2,968
• View Details