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A point mass starts moving in straight line with const.acceleration. After time to,the acceleration changes its sign, remaining the same in magnitude. Determine the time t from the beginning of motion in which the point mass returns to the initial position?
Dear Chilukuri
after to velocity of particle =ato
Distance travell in time to
S1 =0 +1/2 a to2
Time taken from from Point B to C in forward motion is
v=u -at
0=ato -at
t= to
same time willl take to come from point c to b
and from motion B to A time take is
S1 = at0 + 1/2 a t2
1/2 a to2 = at0 + 1/2 a t2
solve for t
t = ( √2 -1 )to
so total time t = to +to +to +( √2 -1 )to
=( √2 +2 )to
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