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Chilukuri Sai Kartik Grade: 12
        

A point mass starts moving in straight line with const.acceleration. After time to,the acceleration changes its sign, remaining the same in magnitude. Determine the time t from the beginning of motion in which the point mass returns to the initial position?

7 years ago

Answers : (2)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear Chilukuri


after tvelocity of particle =ato  


 


6543-1033_7662_untitled.JPG


Distance travell in time to


S1 =0 +1/2 a to2


Time taken from from Point B to C in forward motion is


v=u -at


0=ato -at


t= to


same time willl take to come from point c to b


and from motion B to A  time take is


S1 = at0 + 1/2 a t2


1/2 a to2   = at0 + 1/2 a t2


solve for t


t = ( √2 -1 )to


so total time  t = to +to +to +( √2 -1 )to


                        =( √2 +2 )to


 


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Badiuddin

7 years ago
Badiuddin askIITians.ismu Expert
147 Points
										

6575-63_7662_untitled 2.JPG


Please feel free to post as many doubts on our discussion forum as you can.
 If you find any question Difficult to understand - post it here and we will get you the


answer and detailed solution very quickly.
 We are all IITians and here to help you in your IIT JEE  & AIEEE preparation.


 All the best.
 
Regards,
Askiitians Experts
Badiuddin

7 years ago
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