Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
A particle moves along the x-direction with constant acceleration. The displacemnt, measured from a convenient position, is 2m at time t=0 and is zero when t=10sec. If vel. of the particle is momentary zero when t=6sec, determine the acceleration a and velocity v when t=10sec.
Dear Chilukuri
let convinient point is origin
and initial velocity is u in positive x direction
and acceleration is a in positive x direction
so
S= ut +1/2 * a* t2
-2 = u*10 +1/2 *a*100
-1/5 =u + 5a ....................1
and v=u+at
0 =u+a*6
u=-6a .......................2
solve equation 1 and 2
a=1/5
u=-6/5
so - sign tells that initial velocity is in the negative x dorection.
accleratin at time t = 1/5 m/sec2
velocity v= u +at
=-6/5 + 1/5 *10
=4/5 m/sec
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE & AIEEE preparation.
All the best. Regards,Askiitians ExpertsBadiuddin
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !