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Chilukuri Sai Kartik Grade: 12
        

A particle moves along the x-direction with constant acceleration. The displacemnt, measured from a convenient position, is 2m at time t=0 and is zero when t=10sec. If vel. of the particle is momentary zero when t=6sec, determine the acceleration a and velocity v when t=10sec.

7 years ago

Answers : (1)

Badiuddin askIITians.ismu Expert
147 Points
										

Dear Chilukuri


let convinient point is origin


 and initial velocity is u  in positive x direction


and acceleration is a in positive x direction


so


S= ut +1/2 * a* t2


-2 = u*10 +1/2  *a*100


-1/5 =u + 5a ....................1


 


and v=u+at


     0 =u+a*6


   u=-6a .......................2


 


solve equation 1 and 2


a=1/5


u=-6/5


so - sign tells that initial velocity is in the negative x dorection.


accleratin at time t = 1/5 m/sec2


velocity  v= u +at


               =-6/5 + 1/5 *10


              =4/5 m/sec


  


 




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Badiuddin

7 years ago
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