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`        A particle moves along the x-direction with constant acceleration. The displacemnt, measured from a convenient position, is 2m at time t=0 and is zero when t=10sec. If vel. of the particle is momentary zero when t=6sec, determine the acceleration a and velocity v when t=10sec.`
7 years ago

147 Points
```										Dear Chilukuri
let convinient point is origin
and initial velocity is u  in positive x direction
and acceleration is a in positive x direction
so
S= ut +1/2 * a* t2
-2 = u*10 +1/2  *a*100
-1/5 =u + 5a ....................1

and v=u+at
0 =u+a*6
u=-6a .......................2

solve equation 1 and 2
a=1/5
u=-6/5
so - sign tells that initial velocity is in the negative x dorection.
accleratin at time t = 1/5 m/sec2
velocity  v= u +at
=-6/5 + 1/5 *10
=4/5 m/sec

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7 years ago
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